# NCERT Class 10 Mathematics Chapter 13 Surface Areas and Volumes (For CBSE, ICSE, IAS, NET, NRA 2022)

Get unlimited access to the best preparation resource for ICSE/Class-10 : get questions, notes, tests, video lectures and more- for all subjects of ICSE/Class-10.

## Summary

In this chapter, you have studied the following points:

1. To determine the surface area of an object formed by combining any two of the basic solids, namely, cuboid, cone, cylinder, sphere and hemisphere.

2. To find the volume of objects formed by combining any two of a cuboid, cone, cylinder, sphere and hemisphere.

3. Given a right circular cone, which is sliced through by a plane parallel to its base, when the smaller conical portion is removed, the resulting solid is called a Frustum of a Right Circular Cone.

4. The formulae involving the frustum of a cone are:

(i) Volume of a frustum of a cone = .

(ii) Curved surface area of a frustum of a cone = where .

(iii) Total surface area of frustum of a cone = where h = vertical height of the frustum, l = slant height of the frustum and are radii of the two bases (ends) of the frustum.