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`6300 J//K``1260 J//K``4200 J//K`none of these

Answer :

BSolution :

Let X be The thermal capacity of calorimeter and specific heat of water `=4200 J//kg-K` <br> Heat lost by 0.1 kg of water = Heat gained by water in calorimeter+ Heat gained by calorimeter <br> `implies0.1xx4200xx(60-35)` <br> `=0.2xx4200xx(35-30)+X(35-30)` <br> `10500=4200+5 X implies X=1260 J//K`